Looking at the screenshot, I’d guess it sorted by the ASCII values of the characters, so processes with capitalized names come up first. Still not the ideal sorting, but at least makes some sense.

As someone who tried to self-host it like a month ago (and seemingly still hasn’t got it fully working), I’ll just write out the overview of what I’ve done and let you (and others) comment on how correct and feasible it is.

Since my ISP doesn’t allow me to get a static IP address, I rented a VPS connection and made a wireguard tunnel from the VPS to my computer. This tunnel forwards traffic at all the necessary ports between the two machines. I really wasn’t familiar with all the necessary components for an entire mail server, so I chose mailcow since it packages everything into one single software (well, more like a bunch of docker containers). Another reason I went with mailcow was that I could easily find a github tutorial for how to set up mailcow with wireguard tunneling (it’s a bit outdated IMO, but the changes are minor). Mailcow also gives a nice portal interface listing out all the DNS entries you need to put in place to get it working perfectly.

In the end, I still see a few incoming emails getting dropped and reception time being an hour or so, and I’m not sure if it’s a problem with my tunnel or DNS or something else. But overall, I’d say it was much easier than setting up all the individual services myself.

But does it make jack jork?

Yup it seems crazy to me how deep insights one needs to have to be able to, say, connect the dots between compression and machine learning. And now it looks to me like he has done a lot of the foundational work in these fields. Super cool stuff

Too lazy to check, but is this the Rivest from the RSA algorithm?

Like you said, there’s a metric ton of steps involved in the overall process, and our understanding of each of these ‘levels’ of organization varies quite a bit. Closest to my personal expertise is the sub-cellular and cellular level, for which I would refer you books or papers in developmental biology, developmental genetics, and epigenetics. I can give you a couple bloopers to get you excited though:

When it comes to deciding where different organs will form (again, from a sub-cellular level), it essentially starts from a concentration gradient of certain proteins/chemicals inside the zygotic cell. This gradient then determines the level of activation of other proteins, each level then leading to different biochemical cascades which, once more cells have formed from the zygote, determine which organ systems will come from them. Messing around with this concentration gradient can, thus, dramatically affect an organism’s development, leading to, for example, a body with just ‘left’ organs on both halves, just ‘top’ organs on both halves, missing an entire organ system (like circulatory system and heart) and so on.

A more or less similar process occurs to determine the shape of organs. As a simple example, when some animals with regenerative capabilities (like axolotls) lose a limb, they are able to regrow the limb to the exact same length as before. Turns out, each cell on the periphery of their limb has a certain concentration of receptor proteins on its surface, which acts as a molecular ‘signature’ of that cell’s position in the limb. These signatures provide information on how far to grow the limb for regeneration, and some chemicals, lile retinol, can even override these signatures and fool the organism’s body into regrowing the limb from scratch on top of the place of regeneration.

I hope these examples give you an introduction to the mechanisms involved. There’s obviously a lot more involved, so I would again highly recommend textbooks and research papers if you’re interested.

Indeed, an integer is divisible by 3 if and only if the sum of its digits is divisible by 3.

For proof, take the polynomial representation of an integer n = a_0 * 10^k + a_1 * 10^{k-1} + … + a_k * 1. Note that 10 mod 3 = 1, which means that 10^i mod 3 = (10 mod 3)^i = 1. This makes all powers of 10 = 1 and you’re left with n = a_0 + a_1 + … + a_k. Thus, n is divisible by 3 iff a_0 + a_1 + … + a_k is. Also note that iff answers your question then; all multiples of 3 have to, by definition, have digits whose sum is a multiple of 3

I see your encourageMint and raise you

2. Strairdrac is three crabs in a trenchcoat, now teaching others of his kind how to blend in with humans