• tetris11@lemmy.ml
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    2 days ago

    Oh I see it, but for some reason I was taught to always use $(( arith )) instead of (( arith )) and I guess I’m just wondering what the difference is

    • balsoft@lemmy.ml
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      2 days ago

      The difference is that (( is a “compound command”, similar to [[ (evaluate conditional expression), while $(( )) is “aritmetic expansion”. They behave in almost exactly the same way but are used in different contexts - the former uses “exit codes” while the latter returns a string, so the former would be used where you would expect a command, while the latter would be used where you expect an expression.

      This is similar to how there is ( compound command (run in a subshell), and $( ) (command substitution). You can actually use the former to define a function too (as it’s a compound command):

      real_exit() { exit 1; }
      fake_exit() ( exit 1 )
      

      Calling real_exit will exit from the shell, while calling fake_exit will do nothing as the exit 1 command is executed in a separate subshell. Notice how you can also do the same in a command substition (because it runs in a subshell):

      echo $(echo foo; exit 1)
      

      Will run successfully and output foo.

      It is another one of those unknown, very rarely useful features of bash.