• suicidaleggroll@lemmy.world
    link
    fedilink
    English
    arrow-up
    0
    ·
    edit-2
    3 days ago

    If my math is right…it will have an effect of approximately 0.0000000001 g

    Angular acceleration is r*w^2, so for a normal day that would be 6371000*(2*pi/86400)^2/g = 0.0034345580g

    On this accelerated day, it becomes 6371000*(2*pi/86399.9987)^2/g = 0.0034345581g

    That’s at the equator assuming a radius of 6371 km, which is a decent ballpark, the specific number won’t change the result much.